Find most significant bit of a number X in base Y

Given two positive integers X and Y, the task is to find the MSB of X, in the given base Y.
Examples:

Input: X = 55, Y = 3 
Output: 2 
Explanation: 
55 is 2001 in base 3 with first digit as 2.
Input: X = 123, Y = 10 
Output: 1 
Explanation: 
123 is 123 in base 10 with first digit 1. 

Approach: Let the task to find 1st digit of X = 1234 in base Y = 10, So to get First digit = 1:  

Divide 1234 by 1000 
= X / 10³ 
= X / 10^{Number of Digits in X - 1} 
= X / 10^{log(X) / log(10)} (which is for base 10)  

For any other base, we can replace 10 with Y. Therefore, we can calculate the first digit of a number X in base Y by using the formula:

X / Y^{(log(X)/log(Y))}

Below is the implementation of the above approach:  

// C++ Program to find the
// first digit of X in base Y

#include <bits/stdc++.h>
using namespace std;

// Function to find the first
// digit of X in base Y
void first_digit(int x, int y)
{
    // calculating number of digits of
    // x in base y
    int length = log(x) / log(y) + 1;

    // finding first digit of x in base y
    int first_digit = x / pow(y, length - 1);

    cout << first_digit;
}

// Driver code
int main()
{
    int X = 55, Y = 3;

    first_digit(X, Y);

    return 0;
}

// Java Program to find the
// first digit of X in base Y
import java.util.*;
class GFG{

// Function to find the first
// digit of X in base Y
static void first_digit(int x, int y)
{
    // calculating number of digits of
    // x in base y
    int length = (int)(Math.log(x) / 
                       Math.log(y) + 1);

    // finding first digit of x in base y
    int first_digit = (int)(x / Math.pow(y, 
                                length - 1));

    System.out.println(first_digit);
}

// Driver code
public static void main(String args[])
{
    int X = 55, Y = 3;

    first_digit(X, Y);
}
}

// This code is contributed by AbhiThakur

# Python3 program to find the 
# first digit of X in base Y 
import math

# Function to find the first 
# digit of X in base Y 
def first_digit(x, y):
    
    # Calculating number of digits of 
    # x in base y 
    length = int (math.log(x) / 
                  math.log(y) + 1) 
    
    # Finding first digit of x in base y
    first_digit = x / math.pow(y, length - 1)

    print(int(first_digit))
    
# Driver code 
X = 55
Y = 3

first_digit(X, Y)

# This code is contributed by ishayadav181

// C# Program to find the
// first digit of X in base Y
using System;
class GFG{

// Function to find the first
// digit of X in base Y
static void first_digit(int x, int y)
{
    // calculating number of digits of
    // x in base y
    int length = (int)(Math.Log(x) / 
                       Math.Log(y) + 1);

    // finding first digit of x in base y
    int first_digit = (int)(x / Math.Pow(y, 
                                length - 1));

    Console.Write(first_digit);
}

// Driver code
public static void Main()
{
    int X = 55, Y = 3;

    first_digit(X, Y);
}
}

// This code is contributed by Akanksha_Rai

<script>

// Javascript Program to find the
// first digit of X in base Y

// Function to find the first
// digit of X in base Y
function first_digit(x, y)
{
    // calculating number of digits of
    // x in base y
    var length = parseInt(Math.log(x) / Math.log(y)) + 1;

    // finding first digit of x in base y
    var first_digit = parseInt(x / Math.pow(y, length - 1));

    document.write( first_digit);
}

// Driver code
var X = 55, Y = 3;
first_digit(X, Y);

</script>

2

Time Complexity: O(1)

Auxiliary Space: O(1)