Print Alphabets

Given two char c1 and c2, you need to print all the alphabets starting from c1 to c2 in a single line.

Note: Print all characters with a single space after it and all in a single line. Don't add a new line after printing.

Examples:

Input: c1 = 'a', c2 = 'z'|
Output: "a b c d e f g h i j k l m n o p q r s t u v w x y z "
Explanation: Printed alphabets from a to z.

Input: c1 = 'h', c2 = 'u'
Output: "h i j k l m n o p q r s t u "
Explanation: Printed alphabets from h to u.

[Naive Approach] While Loop - O(n) Time and O(1) Space

The idea is to start from c1 and keep increasing the character until c2 is reached. At each step, print the current character followed by a space.

Working of Approach:

• Start with c1 as the current character.
• Continue the loop while the character is less than or equal to c2.
• Print the current character followed by a space.
• Increment the character to move to the next alphabet.
• Stop when the character becomes greater than c2.

#include <iostream>
using namespace std;

void alphabets(char c1, char c2)
{
    // Traverse from c1 to c2
    while (c1 <= c2)
    {
        cout << c1 << " ";
        c1++;
    }
}

int main()
{
    char c1 = 'h', c2 = 'u';

    alphabets(c1, c2);

    return 0;
}

public class GFG {
    // Traverse from c1 to c2
    static void alphabets(char c1, char c2)
    {
        while (c1 <= c2) {
            System.out.print(c1 + " ");
            c1++;
        }
    }

    public static void main(String[] args)
    {
        char c1 = 'h', c2 = 'u';

        alphabets(c1, c2);
    }
}

def alphabets(c1, c2):
    # Traverse from c1 to c2
    while c1 <= c2:
        print(c1, end=' ')
        c1 = chr(ord(c1) + 1)


if __name__ == '__main__':
    c1 = 'h'
    c2 = 'u'

    alphabets(c1, c2)

using System;

class GFG {
    // Traverse from c1 to c2
    static void alphabets(char c1, char c2)
    {
        while (c1 <= c2) {
            Console.Write(c1 + " ");
            c1++;
        }
    }

    static void Main()
    {
        char c1 = 'h', c2 = 'u';

        alphabets(c1, c2);
    }
}

function alphabets(c1, c2)
{
    // Traverse from c1 to c2
    while (c1 <= c2) {
        process.stdout.write(c1 + "");
        c1 = String.fromCharCode(c1.charCodeAt(0) + 1);
    }
}

// Driver Code
let c1 = "h", c2 = "u";

alphabets(c1, c2);

h i j k l m n o p q r s t u 

[Expected Approach] For Loop for Character Range - O(n) Time and O(1) Space

The idea is to directly iterate from c1 to c2 using a for loop and print every character followed by a space.

Working of Approach:

• Initialize the loop variable with c1.
• Run the loop while the current character is at most c2.
• Print the current character followed by a space.
• Increment the loop variable to get the next alphabet.
• Continue until all characters from c1 to c2 are printed.

Let us understand with an example:
Input: c1 = 'h', c2 = 'u'

• Initialize c1 = 'h' and c2 = 'u', then start the loop with c = 'h'.
• Print each character followed by a space and increment c after every iteration.
• The loop prints characters from h through u in sequence.
• When c becomes 'v', the condition c <= c2 becomes false.
• Therefore, the output is "h i j k l m n o p q r s t u ".

#include <iostream>
using namespace std;

void alphabets(char c1, char c2)
{
    // Traverse from c1 to c2
    for (char c = c1; c <= c2; c++)
    {
        cout << c << " ";
    }
}

int main()
{
    char c1 = 'h', c2 = 'u';

    alphabets(c1, c2);

    return 0;
}

public class GFG {
    // Traverse from c1 to c2
    static void alphabets(char c1, char c2)
    {
        for (char c = c1; c <= c2; c++) {
            System.out.print(c + " ");
        }
    }

    public static void main(String[] args)
    {
        char c1 = 'h', c2 = 'u';

        alphabets(c1, c2);
    }
}

def alphabets(c1, c2):
    # Traverse from c1 to c2
    for c in range(ord(c1), ord(c2) + 1):
        print(chr(c), end=' ')

if __name__ == '__main__':
    c1 = 'h'
    c2 = 'u'

    alphabets(c1, c2)

using System;

class GFG {
    // Traverse from c1 to c2
    static void alphabets(char c1, char c2)
    {
        for (char c = c1; c <= c2; c++) {
            Console.Write(c + " ");
        }
    }

    static void Main()
    {
        char c1 = 'h', c2 = 'u';

        alphabets(c1, c2);
    }
}

function alphabets(c1, c2)
{
    // Traverse from c1 to c2
    for (let c = c1.charCodeAt(0); c <= c2.charCodeAt(0);
         c++) {
        process.stdout.write(String.fromCharCode(c) + "");
    }
}

// Driver Code
let c1 = "h", c2 = "u";

alphabets(c1, c2);

h i j k l m n o p q r s t u