Cross Multiplication Method Practice Questions

Last Updated : 17 Oct, 2026

The cross multiplication method is a mathematical technique used to solve equations involving two fractions or ratios.

Solved Examples

Example 1: Solve the following linear equations using the cross-multiplication method.

  • 2x - 3y = 6
  • 5x - 6y = 8

Given equations are,

2x - 3y = 6 and 5x - 6y = 8

Comparing with a1x + b1y = -c1 and a2x + b2y = -c2

a1 = 2, b1 = -3, c1 = -6

a2 = 5, b2 = -6, c2 = -8

Using Cross Multiplication Method,

x/(b1c2 - b2c1) = y/(c1a2 - c2a1) = 1/(b2a1 -  b1a2)

Substituting all the values

x/[(-3).(-8) - (-6).(-6)] = y/[(-6).(5) - (-8).(2)] = 1/[(-6).(2) - (-3).(5)]

x/[24 - 36] = y/[-30 + 16] = 1/[-12 + 15]

x/(-12) = y/(-14) = 1/(3)

x/(-12) = 1/3

x = -4

y/(-14) = 1/(3)

y = -14/3

Thus, the value of x = -4 and -14/3

Example 2: Solve the following linear equations using the cross-multiplication method.

  • 3x + 4y = 5
  • x + 2y = 6

Given equations are,

3x + 4y = 5 and x + 2y = 6

Comparing with a1x + b1y = -c1 and a2x + b2y = -c2

a1 = 3, b1 = 4, c1 = -5

a2 = 1, b2 = 2, c2 = -6

Using Cross Multiplication Method,

x/(b1c2 - b2c1) = y/(c1a2 - c2a1) = 1/(b2a1 -  b1a2)

Substituting all the values

x/[(4).(-6) - (2).(-5)] = y/[(-5).(1) - (-6).(3)] = 1/[(2).(3) - (4).(1)]

x/[-24 + 10] = y/[-5 + 18] = 1/[6 - 4]

x/(-14) = y/(13) = 1/(2)

x/(-14) = 1/2

x = -7

y/(13) = 1/(2)

y = 13/2

Thus, the value of x = -7 and 13/2

Example 3: Check whether 2x + 3y = 5 and 3x + y = 7 yields a unique solution or not.

Given Equation,

  • 2x + 3y = 5
  • 3x + y = 7

Comparing with a1x + b1y = -c1 and a2x + b2y = -c2

a1 = 2, b1 = 3

a2 = 3, b2 = 1

Using the condition 

a1/a2 ≠ b1/b2

2/3 ≠ 3/1

As the condition holds true the given equations give the unique solution.

Practice Problems

Problem 1: Solve the pair of equations: 2x+y = 7 and 3x−y = 8

Problem 2: Find the values of x and y: 4x+5y=18 and 2x−y=4.

Problem 3: Solve the following system of equations: 3x+2y = 12 and 5x−y = 7

Problem 4: Using the Cross Multiplication Method, find the solution of: 7x + 3y = 20 and 2x + y = 5

Problem 5: Determine the values of x and y: 5x−2y = 16 and 3x+4y = 18

Pascal-1


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