Whole numbers are all the non-negative integers starting from zero: 0, 1, 2, 3, and so on.
Solved Examples
Question 1: Which of the following are whole numbers?
−3, 0, 2.5, 4, 5, −1.2
Solution:
Whole numbers are non-negative integers, which include 0, 1, 2, 3, etc. Therefore, from the list, 0, 4, and 5 are whole numbers. Negative numbers and fractions/decimals are not whole numbers.
Question 2: What is the sum of 7 and 8?
Solution:
Addition of two numbers is straightforward. 7 + 8 = 15.
Question 3: What is the sum of the first 10 whole numbers?
Solution:
The first 10 whole numbers are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
Adding them: 0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = 450.
Thus, answer is 450.
Note: We can also use the formula for sum of n natural numbers.
Question 4: Identify if the following statement is True or False: "The sum of any two whole numbers is always a whole number."
Solution:
Whole numbers are closed under addition, meaning adding two whole numbers always results in another whole number. For example, 2 + 3 = 5, which is a whole number.
Question 5: Find the sum of the squares of the first 5 whole numbers.
Solution:
The first 5 whole numbers are 0, 1, 2, 3, 4.
Their squares are 02, 12, 22, 32, 42.
Calculate each square and then sum them: 02 + 12 + 22 + 32 + 42 = 0 + 1 + 4 + 9 + 16 = 30.
Thus, sum of square of first 5 whole number is 30.
Question 6: A teacher has 4 boxes of markers. Each box contains 12 markers. How many markers does the teacher have in total?
Solution:
Multiply the number of boxes by the number of markers per box: 4 × 12 = 48.
Evaluate 2+3×(4+6)−82 + 3 \times (4 + 6) - 82+3×(4+6)−8.
Solution:
Follow the order of operations (PEMDAS/BODMAS):
2 + 3 × (4 + 6) − 8
First, calculate inside the parentheses: 4 + 6 = 10
Then, multiplication:
3 × 10 = 30
Finally, addition and subtraction:
2 + 30 − 8 = 32−8 = 24
Question 7: Simplify: 216 × 65 + 216 × 35.
Solution :
216 × 65 + 216 × 35 = 216 × (65 + 35)
= 216 × 100
= 21600
Thus, 216 × 65 + 216 × 35 = 21600
Question 8: Find the product by suitable rearrangement: 2 × 1768 × 50
Solution:
2 × 1768 × 50
This expression can be rearranged as:
= (2 × 50) × 1768
= 100 × 1768
= 176800
Therefore, 2 × 1768 × 50 = 176800
Question 9: Find the product using suitable properties: 854 × 102.
Solution:
854 × 102
= 854 × (100 + 2)
= 854 × 100 + 854 × 2 (Using distributive property)
= 85400 + 1708
= 87108
Thus, 854 × 102 = 87108
Question 10: Find the sum by suitable rearrangement. 197 + 234 + 103
Solution:
197 + 234 + 103
This can be rearranged as:
(197 + 103) + 234
= 300 + 234
= 534
Therefore, 197 + 234 + 103 = 534.
Question 11: How many whole numbers are there between 33 and 54?
Solution:
The whole numbers between 33 and 54 are:
34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53
Thus, there are 20 whole numbers between 33 and 54.
Practice Questions
Question 1: What is the sum of the first 100 whole numbers?
Question 2: What is the smallest whole number that is divisible by both 8 and 12?
Question 3: What is the product of the first 10 whole numbers?
Question 4: How many whole numbers are there between 1 and 100 (inclusive) that are divisible by 5?
Question 5: If you add 15 to a certain whole number, the result is 42. What is the number?
Question 6: ( 45 + 32 = ? )
Question 7: ( 120 ÷ 10 × 3 = ? )
Question 8: ( 99 - 44 + 33 = ? )
Question 9: What is 345 + 678?
Question 10: What is 256 × 34?
